如果x^2-3x+1=0,求2x^2-5x-2+3/x^2+1的值

来源:百度知道 编辑:UC知道 时间:2024/05/10 21:32:21
是求2x^2-5x-2+3/(x^2+1)的值

x^2-3x+1=0
x^2+1=3x

x^2-3x+1=0
x^2=3x-1

x^2-3x+1=0
显然x不等于0
所以两边除以x
x-3+1/x=0
x+1/x=3

2x^2-5x-2+3/x^2+1
=2(3x-1)-5x-2+3/3x
=6x-2-5x-2+1/x
=x-4+1/x
=3-4
=-1

x^2-3x+1=0
两边除以x
x-3+1/x=0
x+1/x=3
x^2-3x=-1
x^2+1=3x

2x^2-5x-2+3/x^2+1
=2x^2-6x+x-2+3/3x
=(-2+x-2)+1/x
=x+1/x-4
=3-4
=-1

x^2-3x+1=0所以 x^2=3x-1 所以x=3-1/x

2x^2-5x-2+3/x^2+1=6x-2-5x-2+1/x=x+1/x-4=3-1/x+1/x-4=-1
我这个答案是这题答案2x^2-5x-2+3/(x^2+1)
估计你题错了